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The ratio of earth.s orbital angular mom...

The ratio of earth.s orbital angular momentum (about the Sun) to its mass is `4.4 xx 10^(15) m^(2)s^(-1).` Find the area enclosed by earth.s orbit.

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To find the area enclosed by Earth's orbit around the Sun, we start with the given ratio of Earth's orbital angular momentum to its mass: \[ \frac{L}{M} = 4.4 \times 10^{15} \, \text{m}^2/\text{s} \] where \(L\) is the angular momentum, \(M\) is the mass of the Earth, \(V\) is the orbital velocity, and \(R\) is the radius of the orbit. The angular momentum \(L\) of an object in circular motion is given by: ...
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