If a straight line L with negative slope passing through (8,1) meets the coordinate axes at A and B then minimum value of OA+OB is

A straight line with negative slope passing through the point (1,4) meets the coordinate axes at A and B.The minimum value of OA+OB is equal to

A straight line with negative slope passing through the point (2,8) cuts the cordinate axes at A and B then minimum value of OA+OB (where 0 is origin) is equal to

A straight line l with negative slope passes through (8,2) and cuts the coordinate axes at P and Q. Find absolute minimum value of OP+ OQ where O is the origin-

A straight line L with negative slope passes through the point (8,2) and cuts the positive coordinate axes at the points P and Q .as L varies, the absolute minimum value of (OP+OQ)/2 O is origin is

A straight line L.with negative slope passes through the point (8,2) and cuts the positive coordinate axes at points P and Q, then the correct statement(s) among the following is/are (O is origin)

A line is drawn passing through point P(1,2) to cut positive coordinate axes at A and B . Find minimum area of DeltaPAB .

If a straight line I passing through P(3,4) meets positive co-ordinate axes at A &B such that area of triangle OAB is minimum (where O is origin) then slope of I is

A straight line segment (3,4) in the first quadrant meets the co ordinate axes in A and B.The minimum area of Delta AOB is

a pair of lines passing through the point (3,d) and parallel to coordinate axes