Two point masses of mass 4m and m respectively separated by d distance are revolving under mutual force of attraction. Ratio of their kinetic energies will be

Two point masses of mass 4m and m respectively separated by d distance are revolving under mutual force of attraction. Ration of their kinetic energies will be:

Two particles of masses 4kg and 6kg are separated by a distance of 20cm and are moving towards each other under mutual force of attraction, the position of the point where they meet is

Two identical spheres each of mass M and radius R are separated by a distance 3R. The force of attraction between them is proportional to

Two particles of mass M and 2M are at a distance D apart. Under their mutual force of attraction they start moving towards each other. The acceleration of their centre of mass when they are D/2 apart is :

Two spheres of masses 2M and M are initially at rest at a distance R apart. Due to mutual force of attraction, they approach each other. When they are at separation R//2 , the acceleration of the centre of mass of spheres would be

Two point masses m and M are separated bya distance L . The distance of the centre of mass of the system from m is

10 Two particles of masses m_(1) and m_(2) initially at rest start moving towards each other under their mutual force of attraction. The speed of the centre of mass at any time t, when they are at a distance r apart, is