Two identical batteries, each of e.m.f. 2 volt and internal resistance `1.0` ohm are available to produce heat in an external resistance `R = 0.5` ohm by passing a current through it. The maximum Joulean power that can be developed across R using these batteries is

Two identical batteries each of emf E= 2 volt and internal resistance r=1 ohm are available t . produce heat in an external resistance by passing a current through it. What is the maximum power that can be developed across an external resistance R using these batteries?

Two identical batteries, each of EMF 2V and internal resistance r =1Omega are connected as shown. the maximum power that can be developed across R using these batteries is :

Two indentical batteries, each of emf 2V andinternal resistance r=1Omega are connected as shown. The maximum power that can be developed across R using these batteries is

n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is

Four cell each of emf 2 V and internal resistance 1 ohm are connected n parallel with an external resistance of 6 ohm. The current in the external resistance is

N batteries each of emf E and internal resistance r are first connected in series and then in parallel to an external resistance R. if current through R is same in both cases then.

A storage battery has e.m.f. 15 volts and internal resistance 0.05 ohm . Its terminal voltage when it is delivering 10 ampere is

Two identical cells each of emf epsilon , having negligible internal reistance r, are connercted in parallel with each other across an external resistance R. What is the current through this resistance.

A battery is of emt E and internal resistance r . The value of external resistance R so that the power across eternal resistance is maximum :