A mercury drop of radius 1 cm is sprayed into `10^(6)` dropletes of equal size. Calculates the energy expanded if surface tension of mercury is `35 xx 10^(-3) N//m`.

A menisus drop of radius 1 cm sprayed into 10^(5) droplets of equal size . Calculate the energy expended if surface tension of mercury is 435 xx10^(-3) N/m

A mercury drop of radius 1.0 cm is sprayed into 10^(8) droplets of equal size. Calculate the energy expanded. (Surface tension of mercury = 32 xx 10^(-2) N//m ).

A mercury drop of radius R is sprayed into n droplets of equal size. Calculate the energy expanded if surface tension of mercury is T .

A mecury drop of radius 1 cm is sprayed into 10^(5) droplets of equal size. Calculate the increase in surface energy if surface tension of mercury is 35xx10^(-3)N//m .

A mercury drop of radius 1 cm is sprayed into 10^(6) drops of equil size. The energy expended in joule is (surface tension of mercury is (460xx10^(-3)N//m)

A mercury drop of radius 1.0 cm is sprayed into 10^(6) droplets of equal sizes. The energy expended in this process is (Given, surface tension of mercury is 32 xx 10^(-2) Nm^(-1) )

A mercury drop of radius 1 cm is broken into 10^6 droplets of equal size. The work done is (T=35xx10^-2(N)/(m) )

A mercury drop of radius R splits up into 1000 droplets of equal radii . The change in the surface area is