Home
Class 11
PHYSICS
In the following common emitter circuit ...

In the following common emitter circuit , if `beta = 100 , V_(CE)=7 V , R(C)=2 kOmega and V_(BE) ` negligible , then `I_B` is

Promotional Banner

Similar Questions

Explore conceptually related problems

In the following common emitter circuit if beta=100, V_(CE)=7 V, V_(BE) =Negligible, R_(C)=2 kOmega then I_(B)=?

In a common emitter transistor circuit, the base current is 40 muA, then V_(BE) is -

In the accompanying circuit (Fig. 5.9) the value of beta is 100 . Find I_(B),V_(CE),V_(CE) and V_(BC) , when I_(C) =1.5 mA . Is the transistor in active, cut-off or saturation state ?

In the common emitter circuit as shown in Fig, the value of the current gain is 100. Find I_(B),V_(CE),V_(BE),V_(BC) when I_(C)=1.5mA . The transistor is in active, cutoff or saturation state.

Passage I An n-p-n transistor is used as a voltage amplifier in a commoin emitter circuit given V_(CC)=8V I_(C )=4mA V_(CE)=4V, (V_(BE)=0.6 V, V_(BB)=8V beta_(Dc)=200 The value of load resistqacne is

A transistor connected in common emitter configuration has V_(C C)=8V, V_(L) = 0.5 V and R_(L) = 800 Omega . If its alpha = 0.96 determine (i) collector emitter voltage, (ii) its base current.

In the circuit Fig. the value of beta is 200. Find I_(B), V_(CE), V_(BE) and V_(BC) , when I_(C)=2.5mA . The transistor is in active, cut off or saturation state.

In a transistor connected in a common emitter mode it has, R_(c)=4kOmega, R_(i)=1kOmega, I_(c)=1mA and I_(b)= 20 muA. Find the voltage gain.

In the circuit given in fig. (V_C)=50 V and R=50 Omega . The values of C and (V_R) are