Total number of stereoisomers of compound is:
`CH_(3)-underset(OH)underset(|)CH-underset(Br)underset(|)CH-CH_(3)`

Total number of stereoisomers of given compound will be CH_(3)-underset(Cl)underset(|)(CH)-underset(Cl)underset(|)(CH)-underset(Cl)underset(|)(CH)-CH_(3)

CH_(3)-underset(OH)underset(|)CH-CH_(2)-underset(CH_(3))underset(|)CH-CHO

The number of enantiomers of the compound CH_(3)-underset(Br)underset(|)(CH)-underset(Br)underset(|)(CH)-COOH is

The number of meso from of the given compound is : CH_(3)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-CH_(3)

CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CHO

Total number of stereoisomer of compound CH_(3)-CH=CH-underset(CH_(3))underset(|)CH-CH=CH-CH_(3)

Write the IUPAC name of the compound. CH_(3)-underset(OH)underset(|)CH-CH-underset(O)underset(||)C-CH_(3) .

Write IUPAC name of CH_(3)-underset(Br)underset(|)CH-underset(CHO)underset(|)(C)H-CH_(3)

Number of stereoisomers of the given compound is CH_(3)-CH=CH-underset(OH)underset(|)(CH)-CH_(3)