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A battery of e.m.f 10V and internal resi...

A battery of e.m.f 10V and internal resistance 3Omega is connected to a resistor.If the current in the circuit is 0.5A,then the resistance of the resistor is

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A battery of emf 10V and internal resistance 3 Omega is connected to a resistor. If the current in the circuit is 0.5A, what is the resistance of the resistor ? What is the terminal voltage of the battery when the circuit is closed ?

A battery of emf 10 V and internal resistance 3 Omega is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor ? What is the terminal voltage of the battery when the circuit is closed ?

Knowledge Check

  • A battery having 12V emf and internal resistance 3Omega is connected to a resistor. If the current in the circuit is 1A, then the resistance of resistor and lost voltage of the battery when circuit is closed will be

    A
    `7Omega,7V`
    B
    `8Omega,8V`
    C
    `9Omega,9V`
    D
    `9Omega,10V`

  • A battery of emf 10 V and internal resistance 3Omega is connected to a resistor. The current in the circuit is 0.5 A . The terminal voltage of the battery when the circuit is closed is

    A
    10 V
    B
    0V
    C
    1.5 V
    D
    8.5 V

  • A battery of e mf 10 V and internal resistance 3Omega is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A . then the resistance of the resistor will be

    A
    `19 Omega`
    B
    `17 Omega`
    C
    `10 Omega`
    D
    `12 Omega`

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    Explore conceptually related problems

    A battery of emf 10 V and internal resistance 3 Omega is connected to a resistor. If the current in the circuit is 0.5 A, find (i) the resistance of the resistor, (ii) the terminal voltage of the battery.

    A battery of emf 10 v and internal resistane 3 Omega is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistane of the resistors ? What is the terminal voltage of the battery when the circuit is closed ?

    A battery of EMF 1.4 V and internal resistance 2Omega is connected to resistor of 100Omega resistance through an ammeter. The resistance of the ammeter is (4)/(3)Omega . A voltmeter is also connected to find potential difference across resistor. The ammeter reacds 0.02 A if resistance of voltmeter is 100x then x is

    A battery of emf 15 V and internal resistance of 4Omega is connected to a resistor. If the current in the circuit is 2A and the circuit is closed. Resistance of the resistor and terminal voltage of the battery will be

    A battery having e.m.f. 5 V and internal resistance 0.5 Omega is connected with a resistance of 4.5 Omega then the voltage at the terminals of battery is

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