A polynomial `ax^(3)+bx^(2)+cx+d` in xy -plane intersects x -axis at `(1,0)` and `(-1,0)` and y -axis at `(0,2)`.The value of `b` is :

The curve y=ax^(3)+bx^(2)+cx is inclined at 45^(@) to x-axis at (0,0) but it touches x-axis at (1,0) , then

The curve y=ax^(3)+bx^(2)+cx is inclined by 45^(@) to x-axis at origin and it touches x-axis at (1,0). Then

The curve y=f(x)=ax^(3)+bx^(2)+cx is inclined at 45^(@) to positive direction of x -axis at (0,0), but it touches x -axis at (1,0) then value of ((f''(1)*f''(2))/(2f(2))) is

If the curve y=ax^(3) +bx^(2) +c x is inclined at 45^(@) to x-axis at (0, 0) but touches x-axis at (1, 0) , then

The curve y=ax^(3)+bx^(2)+cx is inclined at 45^(@) to x-axis at (0,0) but it touches x-axis at (1,0) , then a+b+c+10 is

The curve x^(2)+2xy-y^(2)-x-y+1=0 cuts the x -axis at (0,0) at an angle

The polynomial y = p(x) intersects the axes at (-3,0),(0,1),(1,0)and (3,0) Find the zeroes of the polynomial are :

The curve y = ax ^(3) + bx ^(2) + cx + 5 touches the x-axis at P (-2, 0) and cuts the y-axis at a point Q where its gradient is 3, then 2a + 4b is equal to :

Suppose a parabola y = x^(2) - ax-1 intersects the coordinate axes at three points A,B and C, respectively. The circumcircle of DeltaABC intersects the y-axis again at the point D(0,t) . Then the value of t is