In Young's double slit interference experiment the wavelength of light used is `5000A` .If the phase difference between waves reaching a point `p` on the screen is `6 pi` ,then at the point`p` is ?

In Young's double slit intefrence experiment the wavelength of light used is 6000 Å . If the path difference between waves reaching a point P on the screen is 1.5 microns, then at that point P

In a Young's double slit experiment, the central point on the screen is

In Young's double slit experiment, the slits are 3 mm apart. The wavelength of light used is 5000 Å and the distance between the slits and the screen is 90 cm. The fringe width in mm is

In Young's double-slit experiment, the path difference between two interfering waves at a point on the screen is 13.5 times the wavelength. The point is

In a Young's double slit experiment if the slit separation is twice the wavelength of light used then the maximum number of interference maxima is

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4 xx 10^(-7) m . If the width of the fringe on the screen is 4 mm , the distance between screen and slit is

In Young's double-slit experiment, the intensity at a point P on the screen is half the maximum intensity in the interference pattern. If the wavelength of light used is lambda and d is the distance between the slits, the angular separation between point P and the center of the screen is