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Two similar thin equi-convex lenses, of ...

Two similar thin equi-convex lenses, of focal f each, are kept coaxially in contact with each other such that the focal length of the combination is `F_(1)`, When the space between the two lens is filled with glycerin (which has the same refractive index `(mu=1.5)` as that of glass) then the equivlent focal length is `F_(2)`, The ratio `F_(1): F_(2)` will be

A

`3:2`

B

`2:1`

C

`1:2`

D

`2:3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the focal lengths \( F_1 \) and \( F_2 \) of two similar thin equi-convex lenses in two different configurations. ### Step-by-Step Solution: 1. **Understanding the Configuration**: - We have two identical equi-convex lenses, each with a focal length \( f \). - When they are placed in contact with each other, we need to find the focal length \( F_1 \) of the combination. 2. **Finding \( F_1 \)**: - For two thin lenses in contact, the formula for the equivalent focal length \( F \) is given by: \[ \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} \] - Since both lenses are identical, we can write: \[ \frac{1}{F_1} = \frac{1}{f} + \frac{1}{f} = \frac{2}{f} \] - Therefore, the focal length \( F_1 \) is: \[ F_1 = \frac{f}{2} \] 3. **Finding \( F_2 \)**: - Now, when the space between the two lenses is filled with glycerin (which has the same refractive index as glass, \( \mu = 1.5 \)), we need to find the new focal length \( F_2 \). - The effective focal length of the combination can be calculated as: \[ \frac{1}{F_2} = \frac{1}{f} + \frac{1}{f} - \frac{1}{f} \] - The term \( -\frac{1}{f} \) comes from the fact that the space filled with glycerin acts like a concave lens. Thus: \[ \frac{1}{F_2} = \frac{2}{f} - \frac{1}{f} = \frac{1}{f} \] - Therefore, the focal length \( F_2 \) is: \[ F_2 = f \] 4. **Finding the Ratio \( F_1 : F_2 \)**: - Now we can find the ratio of \( F_1 \) to \( F_2 \): \[ \frac{F_1}{F_2} = \frac{\frac{f}{2}}{f} = \frac{1}{2} \] - Thus, the ratio \( F_1 : F_2 \) is: \[ F_1 : F_2 = 1 : 2 \] ### Final Answer: The ratio \( F_1 : F_2 \) is \( 1 : 2 \).

To solve the problem, we need to find the ratio of the focal lengths \( F_1 \) and \( F_2 \) of two similar thin equi-convex lenses in two different configurations. ### Step-by-Step Solution: 1. **Understanding the Configuration**: - We have two identical equi-convex lenses, each with a focal length \( f \). - When they are placed in contact with each other, we need to find the focal length \( F_1 \) of the combination. ...
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