Match the Xenon compounds Column-I with its structure in Column-II and assign the correct code :
`{:("Column-I","Column-II"),((a)XeF_(4),(i)"pyramidal"),((b)XeF_(6),(ii)" square planar"),((c)XeOF_(4),(iii)" distored octahedral"),((d) XeO_(3),(iv)" square pyramidal"):}`

Options

A. `{:(,(a),(b),(c),(d)),((1),(iii),(iv),(i),"(ii)"):}`
B. `{:(,(a),(b),(c),(d)),((2),(i),(ii),(iii),"(iv)"):}`
C. `{:(,(a),(b),(c),(d)),((3),(ii),(iii),(iv),"(i)"):}`
D. `{:(,(a),(b),(c),(d)),((4),(ii),(iii),(i),"(iv)"):}`

Explanation

To solve the problem of matching the Xenon compounds from Column-I with their corresponding structures in Column-II, we will follow a systematic approach to determine the number of lone pairs and the resulting geometry for each compound.

### Step 1: Analyze XeF₄
1. **Valence Electrons Calculation**:
- Xenon (Xe) has 8 valence electrons.
- Fluorine (F) has 7 valence electrons, and there are 4 fluorine atoms.
- Total valence electrons = 8 (from Xe) + 4 × 7 (from F) = 36 electrons.

2. **Sigma Bonds**:
- XeF₄ has 4 sigma bonds (one for each F atom).

3. **Lone Pairs Calculation**:
- Lone pairs = (Total valence electrons - Number of sigma bonds) / 2
- Lone pairs = (36 - 4) / 2 = 16 / 2 = 8 lone pairs.

4. **Coordination Number**:
- Coordination number = Number of lone pairs + Number of sigma bonds = 2 + 4 = 6.

5. **Geometry**:
- The geometry is octahedral due to the coordination number of 6.

6. **Shape**:
- With 2 lone pairs, the shape is square planar.

### Step 2: Analyze XeF₆
1. **Valence Electrons Calculation**:
- Total valence electrons = 8 (from Xe) + 4 × 7 (from F) = 36 electrons.

2. **Sigma Bonds**:
- XeF₆ has 6 sigma bonds.

3. **Lone Pairs Calculation**:
- Lone pairs = (36 - 6) / 2 = 15 / 2 = 7.5, which rounds to 1 lone pair.

4. **Coordination Number**:
- Coordination number = 1 + 6 = 7.

5. **Geometry**:
- The geometry is octahedral.

6. **Shape**:
- With 1 lone pair, the shape is distorted octahedral.

### Step 3: Analyze XeOF₄
1. **Valence Electrons Calculation**:
- Total valence electrons = 8 (from Xe) + 6 (from F) + 6 (from O) = 20 electrons.

2. **Sigma Bonds**:
- XeOF₄ has 5 sigma bonds (4 from F and 1 from O).

3. **Lone Pairs Calculation**:
- Lone pairs = (20 - 5) / 2 = 15 / 2 = 7.5, which rounds to 1 lone pair.

4. **Coordination Number**:
- Coordination number = 1 + 5 = 6.

5. **Geometry**:
- The geometry is octahedral.

6. **Shape**:
- With 1 lone pair, the shape is square pyramidal.

### Step 4: Analyze XeO₃
1. **Valence Electrons Calculation**:
- Total valence electrons = 8 (from Xe) + 3 × 6 (from O) = 26 electrons.

2. **Sigma Bonds**:
- XeO₃ has 3 sigma bonds.

3. **Lone Pairs Calculation**:
- Lone pairs = (26 - 3) / 2 = 23 / 2 = 11.5, which rounds to 1 lone pair.

4. **Coordination Number**:
- Coordination number = 1 + 3 = 4.

5. **Geometry**:
- The geometry is tetrahedral.

6. **Shape**:
- With 1 lone pair, the shape is pyramidal.

### Final Matching
- (a) XeF₄ → (ii) Square Planar
- (b) XeF₆ → (iii) Distorted Octahedral
- (c) XeOF₄ → (iv) Square Pyramidal
- (d) XeO₃ → (i) Pyramidal

### Conclusion
The correct matching code is:
- (a) → (ii)
- (b) → (iii)
- (c) → (iv)
- (d) → (i)