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Which of the following reactions are dis...

Which of the following reactions are disproportionation reaction ?

A

(a) `2Cu^(+)toCu^(2+)+Cu^(0)`

B

(b) `3KMnO_(4)^(2-) + 4H^(+)to2MnO_(4)^(-)+MnO_(2)+2H_(2)O`

C

(c) `2KMnO_(4)overset(triangle)toK_(2)MnO_(4)+MnO_(2)+O_(2)`

D

(d) `2MnO_(4)^(-)+3Mn^(2+)+2H_(2)Oto5MnO_(2)+4H^(+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given reactions are disproportionation reactions, we will analyze each reaction step by step. A disproportionation reaction is a specific type of redox reaction where a single species is simultaneously oxidized and reduced. ### Step-by-Step Solution: 1. **Identify the Reactions**: We have four reactions to analyze: - Reaction A: \( 2 \text{Cu}^+ \rightarrow \text{Cu}^{2+} + \text{Cu}^0 \) - Reaction B: \( 3 \text{KMnO}_4 + 4 \text{H}^+ \rightarrow 2 \text{MnO}_4^{-} + \text{MnO}_2 + 2 \text{H}_2O \) - Reaction C: \( 2 \text{KMnO}_4 \rightarrow \text{K}_2\text{MnO}_4 + \text{MnO}_2 + \text{O}_2 \) - Reaction D: \( 2 \text{MnO}_4^{-} + 3 \text{Mn}^{2+} + 2 \text{H}_2O \rightarrow 5 \text{MnO}_2 + 4 \text{H}^+ \) 2. **Analyze Reaction A**: - In \( 2 \text{Cu}^+ \rightarrow \text{Cu}^{2+} + \text{Cu}^0 \): - The oxidation state of Cu changes from +1 to +2 (oxidation). - The oxidation state of Cu changes from +1 to 0 (reduction). - Since the same element (Cu) is both oxidized and reduced, this is a disproportionation reaction. 3. **Analyze Reaction B**: - In \( 3 \text{KMnO}_4 + 4 \text{H}^+ \rightarrow 2 \text{MnO}_4^{-} + \text{MnO}_2 + 2 \text{H}_2O \): - The oxidation state of Mn in KMnO4 is +7 and in MnO4^- it is +6, while in MnO2 it is +4. - Here, Mn is being reduced from +7 to +4 (reduction) and also being oxidized from +7 to +6 (oxidation). - Therefore, this is also a disproportionation reaction. 4. **Analyze Reaction C**: - In \( 2 \text{KMnO}_4 \rightarrow \text{K}_2\text{MnO}_4 + \text{MnO}_2 + \text{O}_2 \): - The oxidation state of Mn changes from +7 in KMnO4 to +6 in K2MnO4 and +4 in MnO2. - Here, Mn is only being reduced (from +7 to +6 and +4). - Since there is no oxidation occurring, this is not a disproportionation reaction. 5. **Analyze Reaction D**: - In \( 2 \text{MnO}_4^{-} + 3 \text{Mn}^{2+} + 2 \text{H}_2O \rightarrow 5 \text{MnO}_2 + 4 \text{H}^+ \): - The Mn in MnO4^- is +7 and in MnO2 it is +4, while Mn2+ is +2. - Here, MnO4^- is being reduced and Mn2+ is being oxidized, involving different species. - Therefore, this is not a disproportionation reaction. ### Conclusion: The reactions that are disproportionation reactions are: - **Reaction A**: \( 2 \text{Cu}^+ \rightarrow \text{Cu}^{2+} + \text{Cu}^0 \) - **Reaction B**: \( 3 \text{KMnO}_4 + 4 \text{H}^+ \rightarrow 2 \text{MnO}_4^{-} + \text{MnO}_2 + 2 \text{H}_2O \) ### Final Answer: The correct options are **A and B**, which are disproportionation reactions.

To determine which of the given reactions are disproportionation reactions, we will analyze each reaction step by step. A disproportionation reaction is a specific type of redox reaction where a single species is simultaneously oxidized and reduced. ### Step-by-Step Solution: 1. **Identify the Reactions**: We have four reactions to analyze: - Reaction A: \( 2 \text{Cu}^+ \rightarrow \text{Cu}^{2+} + \text{Cu}^0 \) - Reaction B: \( 3 \text{KMnO}_4 + 4 \text{H}^+ \rightarrow 2 \text{MnO}_4^{-} + \text{MnO}_2 + 2 \text{H}_2O \) - Reaction C: \( 2 \text{KMnO}_4 \rightarrow \text{K}_2\text{MnO}_4 + \text{MnO}_2 + \text{O}_2 \) ...
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