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If P represents radiation pressure , C ...

If `P` represents radiation pressure , `C` represents the speed of light , and `Q` represents radiation energy striking a unit area per second , then non - zero integers `x, y, z` such that `P^(x) Q^(y) C^(z)` is dimensionless , find the values of `x, y , and z`.

A

`x = 1, y = 1, z = 1`

B

`x =- 1, y =1, z = 1`

C

`x = 1,y =- 1, z = 1`

D

`x = 1, y = 1, z =- 1`

Text Solution

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The correct Answer is:
To solve the problem of finding the integers \( x, y, z \) such that \( P^x Q^y C^z \) is dimensionless, we start by identifying the dimensions of each variable involved: 1. **Identify the dimensions:** - Radiation pressure \( P \): The dimension of pressure is \( [M L^{-1} T^{-2}] \). - Radiation energy per unit area per second \( Q \): This is equivalent to power per unit area, which has the dimension \( [M L^{-3} T^{-3}] \). - Speed of light \( C \): The dimension of speed is \( [L T^{-1}] \). 2. **Express the dimensions in terms of \( M, L, T \):** - For \( P \): \[ [P] = [M L^{-1} T^{-2}] \] - For \( Q \): \[ [Q] = [M L^{-3} T^{-3}] \] - For \( C \): \[ [C] = [L T^{-1}] \] 3. **Set up the equation for dimensional analysis:** We need to find \( x, y, z \) such that: \[ P^x Q^y C^z \text{ is dimensionless} \] This means: \[ [P^x Q^y C^z] = [M^0 L^0 T^0] \] 4. **Substituting the dimensions:** Substituting the dimensions into the equation gives: \[ [M^{x} L^{-x} T^{-2x}] \cdot [M^{y} L^{-3y} T^{-3y}] \cdot [L^{z} T^{-z}] \] Combining these, we have: \[ [M^{x+y} L^{-x-3y+z} T^{-2x-3y-z}] \] 5. **Setting up the equations:** For the expression to be dimensionless, the exponents of \( M, L, T \) must all equal zero: - From \( M \): \[ x + y = 0 \quad \text{(1)} \] - From \( L \): \[ -x - 3y + z = 0 \quad \text{(2)} \] - From \( T \): \[ -2x - 3y - z = 0 \quad \text{(3)} \] 6. **Solving the equations:** - From equation (1), we can express \( y \) in terms of \( x \): \[ y = -x \] - Substitute \( y = -x \) into equation (2): \[ -x - 3(-x) + z = 0 \implies -x + 3x + z = 0 \implies 2x + z = 0 \implies z = -2x \quad \text{(4)} \] - Substitute \( y = -x \) and \( z = -2x \) into equation (3): \[ -2x - 3(-x) - (-2x) = 0 \implies -2x + 3x + 2x = 0 \implies 3x = 0 \] This does not provide new information, so we use the relationships from (1) and (4). 7. **Choosing a value for \( x \):** Let’s choose \( x = 1 \): - Then from (1): \( y = -1 \) - From (4): \( z = -2 \) Thus, we find: \[ x = 1, \quad y = -1, \quad z = -2 \] 8. **Final answer:** The values of \( x, y, z \) are: \[ x = 1, \quad y = -1, \quad z = -2 \]

To solve the problem of finding the integers \( x, y, z \) such that \( P^x Q^y C^z \) is dimensionless, we start by identifying the dimensions of each variable involved: 1. **Identify the dimensions:** - Radiation pressure \( P \): The dimension of pressure is \( [M L^{-1} T^{-2}] \). - Radiation energy per unit area per second \( Q \): This is equivalent to power per unit area, which has the dimension \( [M L^{-3} T^{-3}] \). - Speed of light \( C \): The dimension of speed is \( [L T^{-1}] \). 2. **Express the dimensions in terms of \( M, L, T \):** ...
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