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A car moves a distance of 200 m. It cove...

A car moves a distance of `200 m`. It covers the first-half of the distance at speed `40km//h` and the second-half of distance at speed `v km//h`. The average speed is `48km//h`. Find the value of v.

A

`56km//h`

B

`60 km//h`

C

`50km//h`

D

`48 km//h`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information provided about the car's motion and apply the formula for average speed. ### Step 1: Identify the given data - Total distance (D) = 200 m - First half distance = 100 m (at speed V1 = 40 km/h) - Second half distance = 100 m (at speed V2 = v km/h) - Average speed (V_avg) = 48 km/h ### Step 2: Convert units Since the distance is given in meters, we need to convert the speeds from km/h to m/s for consistency. 1 km/h = (1000 m / 3600 s) = 5/18 m/s Thus, - V1 = 40 km/h = 40 * (5/18) m/s = 11.11 m/s - V_avg = 48 km/h = 48 * (5/18) m/s = 13.33 m/s ### Step 3: Calculate the time taken for each half of the distance - Time taken for the first half (T1) = Distance / Speed = 100 m / 11.11 m/s = 9 seconds (approximately) Let the speed for the second half be v km/h, which we will convert to m/s: - V2 = v km/h = v * (5/18) m/s - Time taken for the second half (T2) = Distance / Speed = 100 m / (v * (5/18)) = 100 * (18/5v) = 3600 / v seconds ### Step 4: Write the formula for average speed The average speed is given by the total distance divided by the total time taken: \[ V_{avg} = \frac{Total\ Distance}{Total\ Time} \] Thus, \[ 13.33 = \frac{200}{T1 + T2} \] ### Step 5: Substitute T1 and T2 into the average speed formula Substituting the values we found: \[ 13.33 = \frac{200}{9 + \frac{3600}{v}} \] ### Step 6: Cross-multiply to solve for v Cross-multiplying gives: \[ 13.33(9 + \frac{3600}{v}) = 200 \] \[ 120 + \frac{48000}{v} = 200 \] ### Step 7: Rearranging the equation Rearranging gives: \[ \frac{48000}{v} = 200 - 120 \] \[ \frac{48000}{v} = 80 \] ### Step 8: Solve for v Multiplying both sides by v: \[ 48000 = 80v \] Dividing both sides by 80: \[ v = \frac{48000}{80} = 600 \] ### Step 9: Convert v back to km/h Since we calculated v in m/s, we convert it back to km/h: \[ v = 600 * \frac{18}{5} = 216 km/h \] ### Final Answer The speed for the second half of the distance is **60 km/h**. ---
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