Home
Class 12
PHYSICS
A uniform rod of length l and mass m is ...

A uniform rod of length `l` and mass `m` is free to rotate in a vertical plane about `A` as shown in Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is

A

`(3g)/(2 l)`

B

`(2 l)/(3 g)`

C

`(3g)/(2 l^(2))`

D

`"mg" (I)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
a
Promotional Banner

Similar Questions

Explore conceptually related problems

A unifrom rod of length l and mass m is free to rotate in a vertical plane about A , Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (MI "of rod about" A "is" (ml^(2))/(3))

A uniform rod of mass m and length L is free to rotate in the vertical plane about a horizontal axis passing through its end. The rod initially in horizontal position is released. The initial angular acceleration of the rod is:

A uniform rod of length L and mass m is free to rotate about a frictionless pivot at one end as shown in figure. The rod is held at rest in the horizontal position and a coin of mass m is placed at the free end. Now the rod is released The reaction on the coin immediately after the rod starts falling is

A L shaped rod of mass M is free to rotate in a vertical plane about axis A A as shown in figure. Maximum angular acceleration of rod is

A uniform rod of length L is free to rotate in a vertical plane about a fixed horizontal axis through B . The rod begins rotating from rest. The angular velocity omega at angle theta is given as

A uniform rod of legth L is free to rotate in a vertica plane about a fixed horizontal axis through B . The rod begins rotating from rest. The angular velocity omega at angle theta is given as

A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is (ml^ 2 ) / ( 3 ) , the initial angular acceleration of the rod will be

A thin uniform rod of mass M and length L is free to rotate in vertical plane about a horizontal axis passing through one of its ends. The rod is released from horizontal position shown in the figure. Calculate the shear stress developed at the centre of the rod immediately after it is released. Cross sectional area of the rod is A. [For calculation of moment of inertia you can treat it to very thin]

A uniform rod of mass m and length l can rotate in a vertical plane about a smooth horizontal axis point H . a. Find angular acceleration alpha of the rod. just after it is released from initial horizontal position from rest'? b. Calculate the acceleration (tangential and radial) , point A at this moment.

A mass m is connected to a massless rod of length l( and is free to rotate in vertical plane about hinged end of rod. If rod is released from horizontal position and mass "m" collides inelastically at lowest position with identical mass m, as shown in the figure, then the maximum height attained by combined mass will be