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The damping force on an oscillator is di...

The damping force on an oscillator is directly proportional to the velocity. The units of the constant to proportionality are

A

`kg ms^(-1)`

B

`kg ms^(-2)`

C

`kg s^(-1)`

D

`kg s`

Text Solution

AI Generated Solution

The correct Answer is:
To find the units of the constant of proportionality for the damping force that is directly proportional to velocity, we can follow these steps: ### Step 1: Understand the relationship The damping force \( F_d \) is directly proportional to the velocity \( v \). This can be expressed mathematically as: \[ F_d = C \cdot v \] where \( C \) is the constant of proportionality. ### Step 2: Identify the units of force and velocity - The unit of force \( F_d \) is Newton (N). - The unit of velocity \( v \) is meters per second (m/s). ### Step 3: Express the unit of force in terms of base units We know that: \[ 1 \, \text{N} = 1 \, \text{kg} \cdot \text{m/s}^2 \] Thus, the unit of force in base units is: \[ \text{N} = \text{kg} \cdot \text{m/s}^2 \] ### Step 4: Substitute the units into the equation From the equation \( F_d = C \cdot v \), we can rearrange it to find the unit of \( C \): \[ C = \frac{F_d}{v} \] Substituting the units: \[ C = \frac{\text{N}}{\text{m/s}} = \frac{\text{kg} \cdot \text{m/s}^2}{\text{m/s}} \] ### Step 5: Simplify the expression When we simplify the expression: \[ C = \frac{\text{kg} \cdot \text{m/s}^2}{\text{m/s}} = \text{kg} \cdot \frac{\text{s}}{\text{s}^2} = \frac{\text{kg}}{\text{s}} \] ### Conclusion The units of the constant of proportionality \( C \) are: \[ \text{kg/s} \] ### Final Answer The correct option for the units of the constant of proportionality is \( \text{kg/s} \). ---
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