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In a simple harmonic motion, when the di...

In a simple harmonic motion, when the displacement is one-half the amplitude, what fraction of the total energy is kinetic ?
(a) Zero (b) `(1)/(4)` (c) `(1)/(2)` (d) `(3)/(4)`

A

Zero

B

`(1)/(4)`

C

`(1)/(2)`

D

`(3)/(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the fraction of kinetic energy when the displacement is one-half of the amplitude in simple harmonic motion (SHM). Let's break it down step by step: ### Step 1: Define the Variables Let: - Amplitude (A) = A - Displacement (x) = A/2 (since the displacement is one-half the amplitude) ### Step 2: Write the Expression for Kinetic Energy In SHM, the kinetic energy (K.E.) can be expressed as: \[ K.E. = \frac{1}{2} m \omega^2 (A^2 - x^2) \] where: - \( m \) is the mass, - \( \omega \) is the angular frequency, - \( A \) is the amplitude, - \( x \) is the displacement. ### Step 3: Substitute the Displacement Substituting \( x = \frac{A}{2} \) into the kinetic energy formula: \[ K.E. = \frac{1}{2} m \omega^2 \left( A^2 - \left(\frac{A}{2}\right)^2 \right) \] ### Step 4: Simplify the Expression Now simplify the expression: \[ K.E. = \frac{1}{2} m \omega^2 \left( A^2 - \frac{A^2}{4} \right) \] \[ K.E. = \frac{1}{2} m \omega^2 \left( \frac{4A^2}{4} - \frac{A^2}{4} \right) \] \[ K.E. = \frac{1}{2} m \omega^2 \left( \frac{3A^2}{4} \right) \] \[ K.E. = \frac{3}{8} m \omega^2 A^2 \] ### Step 5: Write the Expression for Total Energy The total energy (E) in SHM is given by: \[ E = \frac{1}{2} m \omega^2 A^2 \] ### Step 6: Find the Fraction of Kinetic Energy Now, we need to find the fraction of kinetic energy to total energy: \[ \text{Fraction} = \frac{K.E.}{E} \] Substituting the values we found: \[ \text{Fraction} = \frac{\frac{3}{8} m \omega^2 A^2}{\frac{1}{2} m \omega^2 A^2} \] ### Step 7: Simplify the Fraction Canceling out the common terms: \[ \text{Fraction} = \frac{3/8}{1/2} = \frac{3}{8} \times \frac{2}{1} = \frac{3}{4} \] ### Conclusion Thus, the fraction of the total energy that is kinetic when the displacement is one-half the amplitude is: \[ \boxed{\frac{3}{4}} \]
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