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In bringing an electron towards another ...

In bringing an electron towards another electron, the electrostatic potential energy of the system

A

decreases

B

increases

C

remains same

D

becomes zero

Text Solution

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The correct Answer is:
To solve the problem of how the electrostatic potential energy changes when bringing an electron towards another electron, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electrostatic Potential Energy**: The electrostatic potential energy (U) between two point charges is given by the formula: \[ U = \frac{k \cdot q_1 \cdot q_2}{r} \] where \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the distance between the charges. 2. **Identifying Charges and Distances**: In this case, both charges are electrons, so: \[ q_1 = q_2 = -e \] where \( e \) is the magnitude of the charge of an electron. Initially, the distance between the two electrons is \( r_1 \). 3. **Calculating Initial Potential Energy**: The initial potential energy \( U_i \) when the distance is \( r_1 \) is: \[ U_i = \frac{k \cdot (-e) \cdot (-e)}{r_1} = \frac{k \cdot e^2}{r_1} \] 4. **Bringing the Electron Closer**: When we bring one electron closer to the other, the new distance becomes \( r_2 \) (where \( r_2 < r_1 \)). 5. **Calculating Final Potential Energy**: The final potential energy \( U_f \) at distance \( r_2 \) is: \[ U_f = \frac{k \cdot (-e) \cdot (-e)}{r_2} = \frac{k \cdot e^2}{r_2} \] 6. **Comparing Initial and Final Potential Energies**: Since \( r_2 < r_1 \), we know that: \[ \frac{1}{r_2} > \frac{1}{r_1} \] Therefore, \( U_f > U_i \). 7. **Calculating Change in Potential Energy**: The change in potential energy \( \Delta U \) is given by: \[ \Delta U = U_f - U_i \] Since \( U_f > U_i \), it follows that: \[ \Delta U > 0 \] This indicates that the potential energy of the system increases when bringing the electron closer. 8. **Conclusion**: Thus, the electrostatic potential energy of the system increases when an electron is brought closer to another electron. ### Final Answer: The electrostatic potential energy of the system **increases**.
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