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Two 220 V,100 W bulbs are connected firs...

Two 220 V,100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220 V AC supply line. The power drawn by the combination in each case respectively will be :

A

200 W, 150 W

B

50 W , 200 W

C

50 W , 100 W

D

100 W , 50 W

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the power drawn by two 220 V, 100 W bulbs when connected in series and then in parallel, we can follow these steps: ### Step 1: Calculate the resistance of each bulb The power (P) and voltage (V) of each bulb are given as 100 W and 220 V, respectively. We can use the formula for electrical power to find the resistance (R) of each bulb. \[ R = \frac{V^2}{P} \] Substituting the values: \[ R = \frac{(220)^2}{100} = \frac{48400}{100} = 484 \, \Omega \] ### Step 2: Calculate the total resistance when bulbs are connected in series When two bulbs are connected in series, the total resistance (R_s) is the sum of the individual resistances. \[ R_s = R + R = 2R = 2 \times 484 = 968 \, \Omega \] ### Step 3: Calculate the power drawn in series The power drawn (P_s) when connected in series can be calculated using the formula: \[ P_s = \frac{V^2}{R_s} \] Substituting the values: \[ P_s = \frac{(220)^2}{968} = \frac{48400}{968} \approx 50 \, W \] ### Step 4: Calculate the total resistance when bulbs are connected in parallel When two bulbs are connected in parallel, the total resistance (R_p) can be calculated using the formula: \[ \frac{1}{R_p} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R} \] Thus, \[ R_p = \frac{R}{2} = \frac{484}{2} = 242 \, \Omega \] ### Step 5: Calculate the power drawn in parallel The power drawn (P_p) when connected in parallel can be calculated using the formula: \[ P_p = \frac{V^2}{R_p} \] Substituting the values: \[ P_p = \frac{(220)^2}{242} = \frac{48400}{242} \approx 200 \, W \] ### Final Answer The power drawn by the combination in series is approximately **50 W**, and in parallel is approximately **200 W**. ### Summary - Power in series: **50 W** - Power in parallel: **200 W**
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