Home
Class 12
PHYSICS
An electric kettle has tow heating coils...

An electric kettle has tow heating coils. When one of the coils connected to an AC source, the water in the kettle boils in `10` min. when the other coil is used the water boils in `40` min. if both the coils are connected in parallel, the time taken by the same quantity of water of boil will be

A

25 min

B

15 min

C

8 min

D

4 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the time taken for the water to boil when both heating coils of the electric kettle are connected in parallel. We will use the concept of power and the relationship between time, power, and heat. ### Step-by-Step Solution: 1. **Understand the Problem**: - We have two heating coils in an electric kettle. - Coil 1 boils water in 10 minutes. - Coil 2 boils water in 40 minutes. - We need to find the time taken to boil the same quantity of water when both coils are connected in parallel. 2. **Define Variables**: - Let \( t_1 = 10 \) minutes (time taken by coil 1). - Let \( t_2 = 40 \) minutes (time taken by coil 2). 3. **Calculate Power for Each Coil**: - The power \( P \) of a heating coil can be expressed as: \[ P = \frac{H}{t} \] where \( H \) is the heat required to boil the water and \( t \) is the time taken. - For Coil 1: \[ P_1 = \frac{H}{t_1} = \frac{H}{10} \] - For Coil 2: \[ P_2 = \frac{H}{t_2} = \frac{H}{40} \] 4. **Calculate Total Power When Both Coils Are Connected in Parallel**: - When coils are connected in parallel, the total power \( P_{total} \) is the sum of the individual powers: \[ P_{total} = P_1 + P_2 = \frac{H}{10} + \frac{H}{40} \] - To add these fractions, find a common denominator (which is 40): \[ P_{total} = \frac{4H}{40} + \frac{H}{40} = \frac{5H}{40} = \frac{H}{8} \] 5. **Calculate Time Taken to Boil Water with Both Coils**: - Using the power formula again, we have: \[ P_{total} = \frac{H}{t_{total}} \] - Setting the two expressions for power equal gives: \[ \frac{H}{t_{total}} = \frac{H}{8} \] - Solving for \( t_{total} \): \[ t_{total} = 8 \text{ minutes} \] ### Final Answer: The time taken by the same quantity of water to boil when both coils are connected in parallel is **8 minutes**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

An electric kettle has two coils. When one of these is switched on, the water in the kettle boils in 6 minutes. When the other coil is switched on, the water boils in 3 minutes. If the two coils are connected in series, find the time taken to boil the water in the kettle.

An electric kettle has two heating coils. When one coil is used, water in the kettle boils in 5 minutes, while when second coil is used, same water boils in 10 minutes. If the two coils, connected in parallel are used simultaneously, the same water will boil in time

An electric tea kettle has two heating coils. When one of the coils is switched on , boiling begins in 6 min . When the other coil is switched on , boiling begins in 8 min . In what time will the boiling begin if both coils are switched on simultaneously (i) in series and (ii) in parallel.

An electric bettle has two coils. When one coil is switched on it takes 15 minutes and the other takes 30 minutes to boil certain mass of water. The ratio of times taken by them, when connected in series and in parallel to boil the same mass of water is :

There are two separate coils in a heater . If one col is used then it takes 20 minutes to boil a given amount of water completely. But when its other coil is used then it takes 5 minutes to boil the same amount of water. Calculate the time taken to boil the same amount of water using the same source when the two coils are connected (1) in series and (2) in parallel.

An electric kettle has two coils of same power . When one coil is switched on , it takes 15 min to boil water , and when the second coil is switched on , it takes 30 min . How long will it take to boil water when both the coils are used in i . Series and ii . parallel?

A coil takes 15 min to boil a certain amount of water, another coil takes 20 min for the same process. Time taken to boil the same amount of water when both coil are connected in series

A heater boils certain amount of water in 15 minutes. Another heater boils same amount of water in 10 minutes. Time taken to boil same amount of water when both are used in parallel is

Two heating coils, one of fine wire and the other of thick wire of the same material and of the same length are connected in series and in parallel. Which of the following statement is correct ?

Two containers having boiling water and ice are connected through a conducting metal rod. The whole ice melts in time T. now the rod is cut into two equal parts and both parts are connected in parallel between the containers the time required to melt the same amount of ice will be