Direct current is passed through a copper sulphate solution using platinum electrodes. The elements liberated at the electrones are

Options

A. copper at anode and sulphur at cathode
B. sulphur at anode and copper at cathode
C. oxygen at anode and copper at cathode
D. copper at anode and oxygen at cathode

Answer

To solve the question regarding the elements liberated at the electrodes when direct current is passed through a copper sulfate solution using platinum electrodes, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electrodes**: In this setup, we have two platinum electrodes: the anode (positive electrode) and the cathode (negative electrode).

2. **Understand the Electrolysis Process**: When direct current passes through the copper sulfate (CuSO4) solution, electrolysis occurs. This means that chemical reactions will take place at both electrodes.

3. **Dissociation of Copper Sulfate**: Copper sulfate dissociates in solution into its ions:
\[ \text{CuSO}_4 \rightarrow \text{Cu}^{2+} + \text{SO}_4^{2-} \]
Here, \(\text{Cu}^{2+}\) is the copper ion and \(\text{SO}_4^{2-}\) is the sulfate ion.

4. **Reactions at the Anode**: At the anode, oxidation occurs. The sulfate ions (\(\text{SO}_4^{2-}\)) are attracted to the anode, where they can lose electrons. However, in the case of copper sulfate, the copper ions (\(\text{Cu}^{2+}\)) are more likely to be deposited at the cathode rather than reacting at the anode.

5. **Reactions at the Cathode**: At the cathode, reduction occurs. The positively charged copper ions (\(\text{Cu}^{2+}\)) are attracted to the cathode, where they gain electrons and are reduced to form solid copper:
\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu (s)} \]

6. **Final Products**: Therefore, at the anode, there is no significant reaction involving sulfate ions that liberates a distinct element, while at the cathode, copper is deposited. The sulfate ions remain in solution.

7. **Conclusion**: The elements liberated at the electrodes are copper at the cathode and no significant element at the anode. The correct answer is:
- Copper at the cathode and sulfate ions at the anode.

### Final Answer:
- **Copper at the cathode and no significant element at the anode.**