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A current of 2 A, passing through a cond...

A current of `2 A`, passing through a conductor produces `80 J` of heat in `10 s`. The resistance of the conductor in ohm is:
(1.) 0.5
(2.) 2
(3.) 4
(4.) 20

A

`0.5`

B

`2`

C

`4`

D

`20`

Text Solution

AI Generated Solution

The correct Answer is:
To find the resistance of the conductor, we can use the formula for heat produced in a conductor due to current, which is given by: \[ H = I^2 R t \] Where: - \( H \) = heat produced (in joules) - \( I \) = current (in amperes) - \( R \) = resistance (in ohms) - \( t \) = time (in seconds) Given: - \( H = 80 \, \text{J} \) - \( I = 2 \, \text{A} \) - \( t = 10 \, \text{s} \) ### Step 1: Rearranging the formula We want to find the resistance \( R \). Rearranging the formula gives us: \[ R = \frac{H}{I^2 t} \] ### Step 2: Substituting the values Now we can substitute the known values into the equation: \[ R = \frac{80 \, \text{J}}{(2 \, \text{A})^2 \times 10 \, \text{s}} \] ### Step 3: Calculating \( I^2 \) Calculating \( I^2 \): \[ I^2 = (2 \, \text{A})^2 = 4 \, \text{A}^2 \] ### Step 4: Substituting \( I^2 \) back into the equation Now substituting \( I^2 \) back into the equation for \( R \): \[ R = \frac{80 \, \text{J}}{4 \, \text{A}^2 \times 10 \, \text{s}} \] ### Step 5: Calculating the denominator Calculating the denominator: \[ 4 \, \text{A}^2 \times 10 \, \text{s} = 40 \, \text{A}^2 \cdot \text{s} \] ### Step 6: Final calculation of \( R \) Now, substituting this value back into the equation for \( R \): \[ R = \frac{80 \, \text{J}}{40 \, \text{A}^2 \cdot \text{s}} = 2 \, \Omega \] ### Conclusion The resistance of the conductor is \( R = 2 \, \Omega \). The correct option is (2) 2. ---
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