Current is flowing in a coil of area A and number of turns N, then magnetic moment of the coil ,M is equal to

Options

A. NiA
B. `(Ni)/(A)`
C. `(Ni)/(sqrt(A))`
D. `N^(2)Ai`

Answer

To find the magnetic moment \( M \) of a coil with area \( A \) and number of turns \( N \) carrying a current \( I \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Magnetic Moment**: The magnetic moment \( M \) of a coil is a measure of the strength and orientation of its magnetic field. It depends on the number of turns in the coil, the current flowing through it, and the area of the coil.

2. **Formula for Magnetic Moment**: The magnetic moment \( M \) can be expressed with the formula:
\[ M = N \cdot I \cdot A \]
where:
- \( N \) is the number of turns in the coil,
- \( I \) is the current flowing through the coil,
- \( A \) is the area of the coil.

3. **Substituting Values**: If we have the values for \( N \), \( I \), and \( A \), we can substitute them into the formula to calculate the magnetic moment.

4. **Final Expression**: Thus, the magnetic moment \( M \) of the coil can be expressed as:
\[ M = N \cdot I \cdot A \]

### Conclusion:
The magnetic moment \( M \) of a coil with area \( A \) and number of turns \( N \) carrying a current \( I \) is given by the formula:
\[ M = N \cdot I \cdot A \]