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The magnetic field at a distance r from ...

The magnetic field at a distance r from a long wire carryimg current I is 0.4 T. The magnetic field at a distance 2r is

A

0.2 T

B

0.8 T

C

0.1 T

D

1.6 T

Text Solution

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The correct Answer is:
To solve the problem, we need to understand how the magnetic field around a long straight wire carrying current behaves. The magnetic field \( B \) at a distance \( r \) from a long straight wire carrying current \( I \) is given by the formula: \[ B = \frac{\mu_0 I}{2 \pi r} \] where \( \mu_0 \) is the permeability of free space. ### Step-by-Step Solution: 1. **Identify the Given Information:** - The magnetic field at a distance \( r \) is given as \( B_1 = 0.4 \, T \). - We need to find the magnetic field \( B_2 \) at a distance \( 2r \). 2. **Understand the Relationship:** - The magnetic field \( B \) is inversely proportional to the distance \( r \). This means if the distance doubles, the magnetic field will halve. - Mathematically, we can express this relationship as: \[ \frac{B_1}{B_2} = \frac{r_2}{r_1} \] 3. **Substitute the Known Values:** - Here, \( r_1 = r \) and \( r_2 = 2r \). - Therefore, we can write: \[ \frac{B_1}{B_2} = \frac{2r}{r} \] - This simplifies to: \[ \frac{B_1}{B_2} = 2 \] 4. **Solve for \( B_2 \):** - Rearranging the equation gives us: \[ B_2 = \frac{B_1}{2} \] - Substituting \( B_1 = 0.4 \, T \): \[ B_2 = \frac{0.4}{2} = 0.2 \, T \] 5. **Conclusion:** - The magnetic field at a distance \( 2r \) is \( B_2 = 0.2 \, T \). ### Final Answer: The magnetic field at a distance \( 2r \) is **0.2 T**.
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