Home
Class 12
PHYSICS
The half-life of a radioactive isotope X...

The half-life of a radioactive isotope `X` is `50` yr. It decays to an other element `Y` which is stable. The two elements `X` and `Y` were found to be in the ratio of `1 : 15` in a sample of a give rock. The age of the rock was estimated to be

A

`200 yr`

B

`250 yr`

C

`100 yr`

D

`150 yr`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the age of the rock based on the decay of radioactive isotope `X` to stable element `Y`, we can follow these steps: ### Step 1: Understand the Given Information - The half-life of isotope `X` is `50 years`. - The ratio of `X` to `Y` in the rock sample is `1:15`. ### Step 2: Set Up the Relationship Between `X` and `Y` Let the number of nuclei of `X` be `n_X` and the number of nuclei of `Y` be `n_Y`. According to the given ratio: \[ n_Y = 15 \cdot n_X \] ### Step 3: Determine the Total Initial Nuclei The total number of initial nuclei (before decay) can be expressed as: \[ n_0 = n_X + n_Y = n_X + 15n_X = 16n_X \] ### Step 4: Use the Radioactive Decay Formula The number of remaining nuclei of `X` after time `t` can be expressed using the radioactive decay formula: \[ n_X = n_0 \cdot \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}} \] Where: - \( n_0 \) is the initial amount of `X`. - \( T_{1/2} \) is the half-life of `X` (50 years). - \( t \) is the age of the rock. ### Step 5: Substitute the Expression for `n_0` Substituting \( n_0 = 16n_X \) into the decay formula gives: \[ n_X = 16n_X \cdot \left(\frac{1}{2}\right)^{\frac{t}{50}} \] ### Step 6: Simplify the Equation Dividing both sides by \( n_X \) (assuming \( n_X \neq 0 \)): \[ 1 = 16 \cdot \left(\frac{1}{2}\right)^{\frac{t}{50}} \] ### Step 7: Rearranging the Equation This can be rearranged to: \[ \left(\frac{1}{2}\right)^{\frac{t}{50}} = \frac{1}{16} \] ### Step 8: Express \( \frac{1}{16} \) as a Power of \( \frac{1}{2} \) Since \( \frac{1}{16} = \left(\frac{1}{2}\right)^4 \), we can write: \[ \left(\frac{1}{2}\right)^{\frac{t}{50}} = \left(\frac{1}{2}\right)^4 \] ### Step 9: Equate the Exponents From the equality of the bases, we can equate the exponents: \[ \frac{t}{50} = 4 \] ### Step 10: Solve for \( t \) Multiplying both sides by 50 gives: \[ t = 4 \cdot 50 = 200 \text{ years} \] ### Conclusion The age of the rock is estimated to be **200 years**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The half-life of a radioactive isotope X is 50 years. It decays to another element Y which is stable. The two elements X and Y were found to be in the ratio of 1 : 15 in a sample of a given rock. The age of the rock was estimated to be

The half-life of a radioactive isotope X is 20 yr . It decays to another element Y which is stable. The two elements X and Y were found to be in the ratio 1:7 in a sample of given rock. The age of the rock is estimated to be

A radioactive isotope X with half-life 1.5xx10^(9) yr decays into a stable nucleus Y .A rock sample contains both elements X and Y in the ratio 1 : 15. They age of the rock is

A radioactive isotope X with a half-life of 1.37 xx 109 years decays to Y which is stable. A sample of rock from the moon was found to contain both the elements X and Y which were in the ratio of 1 : 7 . The age of the rock is.

A radioactive isotope X with half-life of 693xx10^(9) years decay to Y which is stable. A sample of rock from of the moon was found to contain both the elements X Y in the mole ratio 1:7 . What is the age of the rock ?

A radio isotope X with a half life 1.4xx10^(9) yr decays of Y which is stable. A sample of the rock from a cave was found to contain X and Y in the ratio 1:7 . The age of the rock is

A radio isotope X with a half life 1.4xx10^(9) yr decays of Y which is stable. A sample of the rock from a cave was found to contain X and Y in the ratio 1:7 . The age of the rock is

The half life of 2g sample of radioactive nuclide 'X' is 15 min. The half life time of 1g sample of X is

The half - line period a radioactive element X is same as the mean life time of another radioactive element Y . Initially both of them have the same number of atoms. Then:

A radioactive element X decays to give two inert gases X is