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After 1 alpha and 2 beta emissions....

After `1 alpha` and `2 beta` emissions.

A

mass number reduces by `2`

B

mass number reduces by `6`

C

atomic number reduces by `2`

D

atomic number remains unchanged

Text Solution

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The correct Answer is:
To solve the problem of what happens to an element after one alpha emission and two beta emissions, we can follow these steps: ### Step 1: Define the Initial Element Let’s assume the initial element has: - Mass number (A) - Atomic number (Z) ### Step 2: Analyze Alpha Emission An alpha particle consists of 2 protons and 2 neutrons. When an element emits an alpha particle: - The mass number decreases by 4 (A - 4) - The atomic number decreases by 2 (Z - 2) So after one alpha emission, the new element will have: - New mass number = A - 4 - New atomic number = Z - 2 ### Step 3: Analyze Beta Emission A beta particle is an electron emitted from the nucleus, which occurs when a neutron is converted into a proton. When an element emits a beta particle: - The mass number remains unchanged (A) - The atomic number increases by 1 (Z + 1) Since we have two beta emissions, we need to apply this change twice: - After the first beta emission: - Mass number = A - 4 (remains the same) - Atomic number = Z - 2 + 1 = Z - 1 - After the second beta emission: - Mass number = A - 4 (remains the same) - Atomic number = Z - 1 + 1 = Z ### Step 4: Combine the Results After one alpha emission and two beta emissions, the resulting element will have: - Mass number = A - 4 - Atomic number = Z ### Final Result Thus, the final state of the element after one alpha and two beta emissions is: - Mass number = A - 4 - Atomic number = Z ### Conclusion From the above analysis, we can conclude that the final element has a mass number decreased by 4 and the atomic number remains unchanged.
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