Complete the equation for the following fission process `._92 U^235 ._0 n^1 rarr ._38 Sr^90 +....`.

Options

A. `._(54)Xe^(143)+3 ._(0)n^(1)`
B. `._(54)Xe^(145)`
C. `._(57)Xe^(142)`
D. `._(54)Xe^(142)+ ._(0)n^(1)`

Answer

To complete the fission process equation given as:

\[ _{92}^{235}U + _{0}^{1}n \rightarrow _{38}^{90}Sr + ? \]

we need to ensure that the total mass number and atomic number are conserved in the nuclear reaction.

### Step 1: Identify the mass and atomic numbers of the reactants
- Uranium-235 (\( _{92}^{235}U \)) has a mass number of 235 and an atomic number of 92.
- The neutron (\( _{0}^{1}n \)) has a mass number of 1 and an atomic number of 0.

**Total mass number of reactants:**
\[ 235 + 1 = 236 \]

**Total atomic number of reactants:**
\[ 92 + 0 = 92 \]

### Step 2: Identify the mass and atomic numbers of the products
We already have one product, Strontium-90 (\( _{38}^{90}Sr \)), which has:
- Mass number = 90
- Atomic number = 38

### Step 3: Calculate the remaining mass and atomic numbers needed for the other product
To find the other product, we need to ensure that the total mass number and atomic number of the products equal those of the reactants.

**Remaining mass number:**
\[ 236 - 90 = 146 \]

**Remaining atomic number:**
\[ 92 - 38 = 54 \]

### Step 4: Identify the other product
The other product must have a mass number of 146 and an atomic number of 54. This corresponds to Xenon-146 (\( _{54}^{146}Xe \)).

### Step 5: Write the complete fission equation
Putting everything together, the complete fission reaction is:

\[ _{92}^{235}U + _{0}^{1}n \rightarrow _{38}^{90}Sr + _{54}^{146}Xe \]

### Final Equation
Thus, the complete equation for the fission process is:

\[ _{92}^{235}U + _{0}^{1}n \rightarrow _{38}^{90}Sr + _{54}^{146}Xe \]