The nuclei `._(6)C^(13) & ._(7)N^(14)` can be described as

Options

A. isotones
B. isobars
C. isotopes of carbon
D. isotopes of nitrogen

Answer

To solve the question regarding the nuclei \( _{6}^{13}C \) and \( _{7}^{14}N \), we need to analyze the properties of these nuclei based on their atomic numbers (Z) and mass numbers (A).

### Step-by-Step Solution:

1. **Identify the Nuclei**:
- The first nucleus is \( _{6}^{13}C \) (Carbon-13).
- The second nucleus is \( _{7}^{14}N \) (Nitrogen-14).

2. **Determine the Number of Neutrons**:
- The number of neutrons (N) in a nucleus can be calculated using the formula:
\[ N = A - Z \]
- For Carbon-13:
- Mass number (A) = 13
- Atomic number (Z) = 6
- Neutrons (N) = \( 13 - 6 = 7 \)
- For Nitrogen-14:
- Mass number (A) = 14
- Atomic number (Z) = 7
- Neutrons (N) = \( 14 - 7 = 7 \)

3. **Compare the Number of Neutrons**:
- Both nuclei have the same number of neutrons:
- Carbon-13 has 7 neutrons.
- Nitrogen-14 has 7 neutrons.

4. **Classify the Nuclei**:
- Nuclei that have the same number of neutrons but different numbers of protons are called **isotones**.
- Since \( _{6}^{13}C \) and \( _{7}^{14}N \) have the same number of neutrons (7), they are classified as isotones.

5. **Evaluate Other Options**:
- **Isobars**: Nuclei with the same mass number (A) but different atomic numbers (Z). Here, the mass numbers are different (13 and 14), so they are not isobars.
- **Isotopes**: Nuclei with the same atomic number (Z) but different mass numbers (A). Here, the atomic numbers are different (6 and 7), so they are not isotopes of carbon or nitrogen.

### Conclusion:
Thus, the correct classification of the nuclei \( _{6}^{13}C \) and \( _{7}^{14}N \) is that they are **isotones**.

### Final Answer:
**Option A: Isotones**