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A speeding motorcyclist sees traffic jam...

A speeding motorcyclist sees traffic jam ahead of him. He slows down to `36 km//h` He finds that traffic has eased and a car moving ahead of him at `18 km//h` is honking at a frequency of 1392 Hz. If the speed of sound is `343m//s`, the frequency of the honk as heard by him will be
(a) 1332 Hz (b) 1372 Hz (c) 1412 Hz (d) 1454 Hz

A

1332 Hz

B

1372 Hz

C

1412 Hz

D

1454 Hz

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the Doppler Effect formula to find the frequency of the honk as heard by the motorcyclist. Here are the steps: ### Step 1: Convert speeds from km/h to m/s - The speed of the motorcyclist is given as 36 km/h. - To convert km/h to m/s, we use the conversion factor \( \frac{5}{18} \). \[ \text{Speed of motorcyclist} = 36 \times \frac{5}{18} = 10 \, \text{m/s} \] - The speed of the car is given as 18 km/h. We will convert it similarly. \[ \text{Speed of car} = 18 \times \frac{5}{18} = 5 \, \text{m/s} \] ### Step 2: Identify the known values - Frequency of the honk \( f = 1392 \, \text{Hz} \) - Speed of sound \( v = 343 \, \text{m/s} \) - Speed of the observer (motorcyclist) \( v_o = 10 \, \text{m/s} \) - Speed of the source (car) \( v_s = 5 \, \text{m/s} \) ### Step 3: Apply the Doppler Effect formula The formula for the apparent frequency \( f' \) as heard by the observer is given by: \[ f' = f \times \frac{v + v_o}{v - v_s} \] Here: - \( f' \) is the frequency heard by the observer (motorcyclist). - \( f \) is the actual frequency of the source (car). - \( v \) is the speed of sound. - \( v_o \) is the speed of the observer (motorcyclist). - \( v_s \) is the speed of the source (car). ### Step 4: Substitute the values into the formula Substituting the known values into the formula: \[ f' = 1392 \times \frac{343 + 10}{343 - 5} \] ### Step 5: Calculate the values Calculate the numerator and denominator: - Numerator: \( 343 + 10 = 353 \) - Denominator: \( 343 - 5 = 338 \) Now substitute these values back into the equation: \[ f' = 1392 \times \frac{353}{338} \] ### Step 6: Perform the multiplication and division Calculating the fraction: \[ \frac{353}{338} \approx 1.041 \] Now multiply this by 1392: \[ f' \approx 1392 \times 1.041 \approx 1454.032 \, \text{Hz} \] ### Step 7: Round to the nearest whole number The final frequency as heard by the motorcyclist is approximately: \[ f' \approx 1454 \, \text{Hz} \] ### Conclusion Thus, the frequency of the honk as heard by the motorcyclist is **1454 Hz**, which corresponds to option (d). ---
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