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For a normal eye, the cornea of eye prov...

For a normal eye, the cornea of eye provides a converging power of `40 D` and the least converging power of the eye lens behind the cornea is `20 D`. Using this information, the distance between the retina and the cornea eye lens can be estimated to be

A

`5 cm`

B

`2.5cm`

C

`1.67 cm`

D

`1.5 cm`

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The correct Answer is:
To find the distance between the retina and the cornea eye lens, we can follow these steps: ### Step 1: Understand the Given Information - The converging power of the cornea (P1) = 40 D (diopters) - The least converging power of the eye lens (P2) = 20 D (diopters) ### Step 2: Calculate the Total Power of the Eye The total power (P) of the eye is the sum of the powers of the cornea and the eye lens: \[ P = P1 + P2 \] Substituting the values: \[ P = 40 \, D + 20 \, D = 60 \, D \] ### Step 3: Calculate the Focal Length of the Eye The focal length (F) can be calculated using the formula: \[ F = \frac{1}{P} \] Substituting the total power: \[ F = \frac{1}{60 \, D} \] Since 1 D = 1 m⁻¹, we convert this to centimeters: \[ F = \frac{100}{60} \, cm = \frac{10}{6} \, cm = \frac{5}{3} \, cm \] ### Step 4: Final Result The focal length of the eye, which represents the distance between the cornea eye lens and the retina, is: \[ F \approx 1.67 \, cm \] Thus, the distance between the retina and the cornea eye lens is approximately **1.67 cm**. ---
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