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Photoelectric emission occurs only when ...

Photoelectric emission occurs only when the incident light has more than a certain minimum

A

wavelength

B

intensity

C

frequency

D

power

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The correct Answer is:
To solve the question regarding photoelectric emission, we will follow these steps: ### Step 1: Understand the Photoelectric Effect The photoelectric effect is the phenomenon where electrons are emitted from a material (usually a metal) when it is exposed to light of sufficient frequency. This effect is explained by Einstein’s photoelectric equation. ### Step 2: Write the Photoelectric Equation Einstein's photoelectric equation is given by: \[ KE_{\text{max}} = h\nu - h\nu_0 \] Where: - \( KE_{\text{max}} \) is the maximum kinetic energy of the emitted electrons. - \( h \) is Planck's constant. - \( \nu \) is the frequency of the incident light. - \( \nu_0 \) is the threshold frequency (minimum frequency required for photoelectric emission). ### Step 3: Determine the Condition for Emission For photoelectric emission to occur, the maximum kinetic energy must be greater than zero: \[ KE_{\text{max}} > 0 \] This leads to the condition: \[ h\nu - h\nu_0 > 0 \] Simplifying this, we find: \[ h\nu > h\nu_0 \] Dividing by \( h \) (since \( h \) is a positive constant): \[ \nu > \nu_0 \] ### Step 4: Identify the Minimum Frequency The minimum frequency \( \nu_0 \) is known as the threshold frequency. It is the frequency below which no photoelectric emission occurs, regardless of the intensity of the light. ### Step 5: Conclusion Thus, we conclude that photoelectric emission occurs only when the incident light has a frequency greater than the threshold frequency \( \nu_0 \). ### Final Answer Photoelectric emission occurs only when the incident light has more than a certain minimum frequency, known as the threshold frequency. ---
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