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The energy of a photon of wavelength lam...

The energy of a photon of wavelength `lambda` is

A

`hclambda`

B

`(hc)/(lambda)`

C

`(lambda)/(hc)`

D

`lambdah/c`

Text Solution

AI Generated Solution

The correct Answer is:
To find the energy of a photon with a wavelength \( \lambda \), we can follow these steps: ### Step 1: Understand the relationship between energy and frequency The energy \( E \) of a photon is directly proportional to its frequency \( \nu \). This relationship is given by the equation: \[ E = h \nu \] where \( h \) is Planck's constant. ### Step 2: Relate frequency to wavelength We know the relationship between the speed of light \( c \), frequency \( \nu \), and wavelength \( \lambda \) is given by: \[ c = \nu \lambda \] From this equation, we can express frequency \( \nu \) in terms of wavelength \( \lambda \): \[ \nu = \frac{c}{\lambda} \] ### Step 3: Substitute frequency into the energy equation Now, we can substitute the expression for frequency \( \nu \) into the energy equation: \[ E = h \nu = h \left(\frac{c}{\lambda}\right) \] ### Step 4: Simplify the equation This simplifies to: \[ E = \frac{hc}{\lambda} \] This equation gives us the energy of a photon in terms of its wavelength \( \lambda \). ### Final Answer Thus, the energy of a photon of wavelength \( \lambda \) is: \[ E = \frac{hc}{\lambda} \] ---
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