Home
Class 12
PHYSICS
In a Rutherford scattering experiment wh...

In a Rutherford scattering experiment when a projectile of charge Z1 and mass M1 approaches a target nucleus of charge Z2 and mass M2, the distance of closest approach is r0. The energy of the projectile is :

A

directly proportional to `M_(1)xxM_(2)`

B

directly proportional to `Z_(1)Z_(2)`

C

inversely proportional to `Z_(1)`

D

Directly proportional to mass `M_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

In a Rutherford scattering experiment when a projectile of charge Z_(1) and mass M_(1) approaches s target nucleus of charge Z_(2) and mass M_(2) , te distance of closed approach is r_(0) . The energy of the projectile is

In a Rutherford scattering experiment when a projectile of change Z_(1) and mass M_(1) approaches s target nucleus of change Z_(2) and mass M_(2) , te distance of closed approach is r_(0) . The energy of the projectile is

An alpha nucleus of energy (1)/(2)m nu^(2) bombards a heavy nucleus of charge Ze . Then the distance of closed approach for the alpha nucleus will be proportional to

An alpha nucleus of energy (1)/(2)m nu^(2) bombards a heavy nucleus of charge Ze . Then the distance of closed approach for the alpha nucleus will be proportional to

When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as

When an alpha- particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on m as :

When an alpha- particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on m as :

An alpha- paticle approaches the target nucleus of copper (Z = 29) in such a way that the value of impact parameter is zero. The distance of closest approach will be

Distance of closest approach when a 5.0MeV proton approaches a gold nucleus is (Z=79)

In alpha-particle scattering experiment, the expression of distance of closest approach ( r_0 )is (symbols have their usual meanings)