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Consider an electron in the nth orbit of...

Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength `lambda` of that electron as

A

`(0.529)nlambda`

B

`sqrt(nlambda)`

C

`(13.6)lambda`

D

`nlambda`

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The correct Answer is:
To solve the problem of expressing the circumference of the nth orbit of a hydrogen atom in terms of the de Broglie wavelength (λ) of the electron, we can follow these steps: ### Step 1: Understand the de Broglie wavelength The de Broglie wavelength (λ) of a particle is given by the formula: \[ \lambda = \frac{h}{p} \] where \( h \) is Planck's constant and \( p \) is the momentum of the particle. For an electron, the momentum \( p \) can be expressed as: \[ p = mv \] where \( m \) is the mass of the electron and \( v \) is its velocity. ### Step 2: Write the expression for the circumference of the orbit The circumference \( C \) of the nth orbit of a hydrogen atom is given by: \[ C = 2\pi r \] where \( r \) is the radius of the nth orbit. ### Step 3: Use the Bohr model to relate angular momentum and radius According to the Bohr model, the angular momentum \( L \) of the electron in the nth orbit is quantized and given by: \[ L = mvr = \frac{nh}{2\pi} \] where \( n \) is the principal quantum number. ### Step 4: Express the radius in terms of de Broglie wavelength From the angular momentum equation, we can express \( r \) as: \[ r = \frac{nh}{2\pi mv} \] Now, we can substitute the expression for momentum \( p = mv \) into the de Broglie wavelength formula: \[ \lambda = \frac{h}{mv} \] Thus, we can write: \[ mv = \frac{h}{\lambda} \] Substituting this back into the expression for \( r \): \[ r = \frac{nh}{2\pi \left(\frac{h}{\lambda}\right)} = \frac{n\lambda}{2\pi} \] ### Step 5: Substitute \( r \) back into the circumference formula Now, substituting \( r \) into the circumference formula: \[ C = 2\pi r = 2\pi \left(\frac{n\lambda}{2\pi}\right) \] The \( 2\pi \) terms cancel out: \[ C = n\lambda \] ### Final Answer Thus, the circumference of the nth orbit of a hydrogen atom can be expressed as: \[ C = n\lambda \]
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