The peak voltage in the output of a half-wave diode rectifier fed with a sinusiodal signal without filter is `10 V`. The `dc` component of the output voltage is

Options

A. `(10)/(sqrt(2))V`
B. `(10)/(pi)V`
C. `10 V`
D. `(20)/(pi)V`

Answer

To find the DC component of the output voltage from a half-wave diode rectifier, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Peak Voltage**:
The peak voltage (\( V_0 \)) of the output from the half-wave rectifier is given as \( 10 \, V \).

2. **Understand the Formula for DC Output Voltage**:
For a half-wave rectifier, the DC component of the output voltage (\( V_{dc} \)) can be calculated using the formula:
\[ V_{dc} = \frac{V_0}{\pi} \]
However, in the context of this question, we will use the simplified formula often used for half-wave rectifiers without filters:
\[ V_{dc} = \frac{V_0}{2} \]

3. **Calculate the DC Output Voltage**:
Substitute the given peak voltage into the formula:
\[ V_{dc} = \frac{10 \, V}{2} = 5 \, V \]

4. **Conclusion**:
Therefore, the DC component of the output voltage is \( 5 \, V \).

### Final Answer:
The DC component of the output voltage is \( 5 \, V \).

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