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In which of the following figures, junct...

In which of the following figures, junction diode is forward biased?

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which figure the junction diode is forward biased, we need to understand the concept of forward biasing in a PN junction diode. ### Step-by-Step Solution: 1. **Identify the PN Junction**: - A PN junction diode consists of two regions: the P-type (positive) and the N-type (negative). The P-type region has an abundance of holes (positive charge carriers), while the N-type region has an abundance of electrons (negative charge carriers). 2. **Understand Forward Biasing**: - A diode is said to be forward biased when the P-type side is connected to a higher potential (positive voltage) than the N-type side. This allows current to flow through the diode. 3. **Analyze the Given Figures**: - We need to look at the voltage levels in each figure and compare the potentials of the P and N sides of the diode. 4. **Determine the Voltage Conditions**: - For each figure, we will check the voltage at the P side and the N side: - If the voltage at the P side (V_P) is greater than the voltage at the N side (V_N), then the diode is forward biased. - Mathematically, this can be expressed as: V_P > V_N. 5. **Evaluate Each Option**: - **Option 0**: V_P = 0 V, V_N = -2 V → 0 > -2 (Forward biased) - **Option 1**: V_P = -2 V, V_N = 0 V → -2 < 0 (Reverse biased) - **Option 2**: V_P = 2 V, V_N = 5 V → 2 < 5 (Reverse biased) - **Option 3**: V_P = 5 V, V_N = 0 V → 5 > 0 (Forward biased) 6. **Conclusion**: - The figures that show the diode as forward biased are those where the P side voltage is greater than the N side voltage. Based on our analysis, the correct options are 0 and 3. ### Final Answer: The junction diode is forward biased in figures 0 and 3.
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