In a common base ampifier , the phase difference between the input signal and output voltage is

Options

A. zero
B. `(pi)/(4)`
C. `(pi)/(2)`
D. `pi`

Answer

To determine the phase difference between the input signal and the output voltage in a common base amplifier, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Configuration**:
- In a common base amplifier, the input signal is applied to the emitter terminal, and the output is taken from the collector terminal.

2. **Identify Phase Relationships**:
- In a common base configuration, the input and output signals are related in such a way that the output voltage is in phase with the input voltage.

3. **Define Phase Difference**:
- The phase difference (Δφ) between the input signal and the output voltage can be expressed as:
\[ \Delta \phi = \phi_{out} - \phi_{in} \]
- Where \( \phi_{out} \) is the phase of the output voltage and \( \phi_{in} \) is the phase of the input voltage.

4. **Determine the Phases**:
- Since the output voltage is in phase with the input voltage in a common base amplifier, we can say:
\[ \phi_{out} = \phi_{in} \]

5. **Calculate the Phase Difference**:
- Substituting the phase values into the phase difference formula:
\[ \Delta \phi = \phi_{out} - \phi_{in} = \phi_{in} - \phi_{in} = 0 \]

6. **Conclusion**:
- Therefore, the phase difference between the input signal and the output voltage in a common base amplifier is **0 degrees**.

### Final Answer:
The phase difference between the input signal and output voltage in a common base amplifier is **0 degrees**.

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