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Rate of heat flow through a cylindrical ...

Rate of heat flow through a cylindrical rod is `H_(1)`. Temperatures of ends of rod are `T_(1)` and `T_(2)`. If all the dimensions of rod become double and temperature difference remains same and rate of heat flow becomes `H_(2)`. Then `(H_(1))/(H_(2))` is `0.x`. Find value of x.

A

`H_(2) = 2H_(1)`

B

`H_(2) = (H_(1))/(2)`

C

`H_(2) = (H_(1))/(4)`

D

`H_(2) = 4H_(1)`

Text Solution

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The correct Answer is:
a
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