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A black body has maximum wavelength lamb...

A black body has maximum wavelength `lambda_(m)` at temperature `2000 K`. Its corresponding wavelength at temperature 3000 will be

A

`(2)/(3) lambda`

B

`(16)/(81) lambda`

C

`(81)/(16) lambda`

D

`(4)/(3) lambda`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use Wien's Displacement Law, which states that the product of the maximum wavelength (\( \lambda_m \)) and the absolute temperature (T) of a black body is a constant. This can be mathematically expressed as: \[ \lambda_m T = \text{constant} \] ### Step-by-Step Solution: 1. **Identify the given values:** - Maximum wavelength at temperature \( T_1 = 2000 \, K \) is \( \lambda_m \). - We need to find the maximum wavelength \( \lambda_2 \) at temperature \( T_2 = 3000 \, K \). 2. **Apply Wien's Displacement Law:** According to the law, we can write: \[ \lambda_m T_1 = \lambda_2 T_2 \] 3. **Substitute the known values:** Substitute \( T_1 \) and \( T_2 \) into the equation: \[ \lambda_m \cdot 2000 = \lambda_2 \cdot 3000 \] 4. **Rearrange the equation to solve for \( \lambda_2 \):** To isolate \( \lambda_2 \), we rearrange the equation: \[ \lambda_2 = \frac{\lambda_m \cdot 2000}{3000} \] 5. **Simplify the expression:** This can be simplified to: \[ \lambda_2 = \lambda_m \cdot \frac{2000}{3000} = \lambda_m \cdot \frac{2}{3} \] 6. **Conclusion:** Thus, the corresponding wavelength at temperature \( 3000 \, K \) is: \[ \lambda_2 = \frac{2}{3} \lambda_m \]
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