The gases carbon-monoxide (CO) and nitrogen at the same temperature have kinetic energies `E_(1)` and `E_(2)` respectively. Then

Options

A. `E_(1) = E_(2)`
B. `E_(1) gt E_(2)`
C. `E_(1) lt E_(2)`
D. `E_(1)` and `E_(2)` cannot be compared

Answer

To solve the problem of comparing the kinetic energies of carbon monoxide (CO) and nitrogen (N2) at the same temperature, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Kinetic Energy Formula**:
The average kinetic energy (KE) per molecule of an ideal gas is given by the formula:
\[ KE = \frac{3}{2} k T \]
where \( k \) is the Boltzmann constant and \( T \) is the absolute temperature in Kelvin.

2. **Identify the Gases**:
We are comparing carbon monoxide (CO) and nitrogen (N2). Both gases behave as ideal gases under normal conditions.

3. **Recognize the Temperature Condition**:
Since both gases are at the same temperature, we can denote this temperature as \( T \).

4. **Calculate Kinetic Energies**:
For carbon monoxide (CO):
\[ E_1 = \frac{3}{2} k T \]
For nitrogen (N2):
\[ E_2 = \frac{3}{2} k T \]

5. **Compare the Kinetic Energies**:
Since both expressions for kinetic energy are identical, we can conclude:
\[ E_1 = E_2 \]

6. **Final Relation**:
Therefore, the relation between the kinetic energies of carbon monoxide and nitrogen at the same temperature is:
\[ E_1 = E_2 \]

### Conclusion:
The kinetic energies of carbon monoxide and nitrogen at the same temperature are equal.