The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)

Options

A. `6xx10^(23)`
B. `6xx10^(20)`
C. `3.75xx10^(20)`
D. `7.48xx10^(23)`

Explanation

To solve the problem of finding the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds, we can follow these steps:

### Step 1: Calculate the total charge transferred
The total charge (Q) transferred during electrolysis can be calculated using the formula:
\[ Q = I \times t \]
where:
- \( I \) is the current in amperes (A)
- \( t \) is the time in seconds (s)

Given:
- \( I = 1 \, \text{A} \)
- \( t = 60 \, \text{s} \)

Substituting the values:
\[ Q = 1 \, \text{A} \times 60 \, \text{s} = 60 \, \text{C} \]

### Step 2: Determine the charge of a single electron
The charge of a single electron (e) is given as:
\[ e = 1.60 \times 10^{-19} \, \text{C} \]

### Step 3: Calculate the number of electrons transferred
To find the number of electrons (n) transferred, we can use the formula:
\[ n = \frac{Q}{e} \]

Substituting the values we have:
\[ n = \frac{60 \, \text{C}}{1.60 \times 10^{-19} \, \text{C}} \]

### Step 4: Perform the calculation
Calculating the above expression:
\[ n = \frac{60}{1.60 \times 10^{-19}} \]
\[ n = 3.75 \times 10^{20} \]

### Conclusion
Thus, the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is:
\[ n = 3.75 \times 10^{20} \, \text{electrons} \]