Calculate the equilibrium constant of the reation
`Cu(s)+2Ag^(+)(aq)toCu^(2+)(aq)+2Ag(s)`
`E_((cell))^(Ө)=0.46V`

Options

A. `2.0xx10^(10)`
B. `4.0xx10^(10)`
C. `4.0xx10^(15)`
D. `2.4xx10^(10)`

Answer

C

Explanation

( c) `Cu(s)+2Ag^(2+)(aq) to Cu^(2+) (aq)+2Ag(s)`
`E^(@)=0.46 V " at " 298 K`
`RT ln K= nFE^(@)`
`IN K=(nFE^(@))/(RT)`
`ln K=(2xx0.46)/(0.0591)`
`K=3.68xx10^(15)~~4xx10^(15)`