The equivalent conductance of `Ba^(2+)` and `Cl^-` are respectively 127 and 76 `"ohm"^(-1) cm^2 eq^(-1)` at infinite dilution. What will be the equivalent conductance of `BaCl_2` at infinite dilution ?

Options

A. 139.52
B. 203
C. 279
D. 101.5

Answer

A

Explanation

(a)The equivalent conductance of `BaCl_(2)` at infinite dilution.
`lambda_(oo) " of " BaCl_(2)=(1)/(2) lambda_(oo) " of " Ba^(2+) + lambda_(oo) " of " Cl^(-)`
`=(127)/(2)+76=139.5`