The energy absorbed by each molecule `(A_2)` of a substance is `4.4 xx 10^-19 J` and bond energy per molecule is `4.0 xx 10^-19 J`. The kinetic energy of the molecule per atom will be.

Options

A. `2.0xx10^(-20) J`
B. `2.2xx10^(-19)J`
C. `2.0xx10^(-19)J`
D. `4.0xx10^(-20)J`

Explanation

To find the kinetic energy of each atom in the molecule \( A_2 \), we can follow these steps:

### Step 1: Understand the given values
We have:
- Energy absorbed by each molecule, \( E_{absorbed} = 4.4 \times 10^{-19} \, J \)
- Bond energy per molecule, \( E_{bond} = 4.0 \times 10^{-19} \, J \)
- The molecule \( A_2 \) consists of 2 atoms.

### Step 2: Calculate the energy available for kinetic energy
The kinetic energy per atom can be calculated using the formula:
\[ KE_{per \, atom} = \frac{E_{absorbed} - E_{bond}}{n} \]
where \( n \) is the number of atoms in the molecule. Here, \( n = 2 \) for \( A_2 \).

### Step 3: Substitute the values into the formula
Substituting the values we have:
\[ KE_{per \, atom} = \frac{4.4 \times 10^{-19} \, J - 4.0 \times 10^{-19} \, J}{2} \]

### Step 4: Perform the subtraction
Calculating the numerator:
\[ 4.4 \times 10^{-19} \, J - 4.0 \times 10^{-19} \, J = 0.4 \times 10^{-19} \, J \]

### Step 5: Divide by the number of atoms
Now, divide by 2:
\[ KE_{per \, atom} = \frac{0.4 \times 10^{-19} \, J}{2} = 0.2 \times 10^{-19} \, J \]

### Step 6: Express in standard form
Expressing \( 0.2 \times 10^{-19} \, J \) in standard form gives:
\[ KE_{per \, atom} = 2.0 \times 10^{-20} \, J \]

### Final Answer
The kinetic energy of the molecule per atom is:
\[ \boxed{2.0 \times 10^{-20} \, J} \]