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The energy of a photon is given as 3.03x...

The energy of a photon is given as `3.03xx10^(-19)J`. The wavelength of the photon is

A

6.56 nm

B

65.6 nm

C

656 nm

D

0.656 nm

Text Solution

Verified by Experts

The correct Answer is:
C
(c) According to formula =, `E=(hc)/(lambda)(v=(c)/(lambda))`
Energy E=hv
`3.03xx10^(-19)=(hc)/(lambda)`
`lambda=(6.63xx10^(-34)xx3.0xx10^(8))/(3.03xx10^(-19))`
`=6.56xx10^(-7) m`
`=6.56xx10^(-7)xx10^(9)nm`
=`6.56xx10^(2) nm`
`=656 nm`
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