`""_(92)U""^(235)` nucleus absorbes a neutron and disintegrate into `""_(54)Xe""^(139),""_(38)Sr""^(94)`, and x neutrons x is

Options

A. 3-neutrons
B. 2-neutrons
C. `alpha`particle
D. `beta`particle

Explanation

To solve the problem, we need to analyze the nuclear reaction involving the absorption of a neutron by Uranium-235 and the subsequent disintegration into Xenon-139, Strontium-94, and a certain number of neutrons (x).

### Step-by-Step Solution:

1. **Identify the Initial and Final Nuclei**:
- The initial nucleus is Uranium-235, denoted as \( _{92}^{235}U \).
- It absorbs a neutron, which can be represented as \( _{0}^{1}n \) (where 0 is the atomic number and 1 is the mass number of the neutron).
- The final products are Xenon-139, denoted as \( _{54}^{139}Xe \), Strontium-94, denoted as \( _{38}^{94}Sr \), and x neutrons.

2. **Write the Nuclear Reaction**:
\[ _{92}^{235}U + _{0}^{1}n \rightarrow _{54}^{139}Xe + _{38}^{94}Sr + x \cdot _{0}^{1}n \]

3. **Conservation of Atomic Number**:
- The total atomic number on the left side (reactants) must equal the total atomic number on the right side (products).
- Left side: \( 92 + 0 = 92 \)
- Right side: \( 54 + 38 + 0 \cdot x = 92 \)
- This shows that the atomic numbers are balanced.

4. **Conservation of Mass Number**:
- The total mass number on the left side must equal the total mass number on the right side.
- Left side: \( 235 + 1 = 236 \)
- Right side: \( 139 + 94 + 1 \cdot x = 233 + x \)
- Setting these equal gives:
\[ 236 = 139 + 94 + x \]
\[ 236 = 233 + x \]

5. **Solve for x**:
- Rearranging the equation gives:
\[ x = 236 - 233 = 3 \]
- Therefore, \( x = 3 \).

6. **Conclusion**:
- The number of neutrons produced in the reaction is 3.

### Final Answer:
The value of x is 3.