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If bX^(a) species emit firstly a positro...

If `bX^(a)` species emit firstly a positron then two `alpha` and `beta` last one `alpha` is also emitted and finally convert in `dY^(c )` species so correct the relation is

A

a=c+12,d=b-5

B

a=c-8,d=b-1

C

a=c-6,d=b-0

D

a=c-4,d=b-2

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the decay process of the species \( bX^{(a)} \) and derive the relationships between the mass numbers and atomic numbers of the parent and daughter species. Here is a step-by-step solution: ### Step 1: Identify the Initial and Final Species - The initial species is \( bX^{(a)} \) where: - Mass number (A) = \( a \) - Atomic number (Z) = \( b \) - The final species after decay is \( dY^{(c)} \) where: - Mass number (C) = \( c \) - Atomic number (D) = \( d \) ### Step 2: List the Emissions According to the problem, the emissions during the decay process are: 1. One positron (\( \beta^+ \)) 2. Two alpha particles (\( \alpha \)) 3. One beta particle (\( \beta^- \)) 4. One alpha particle (\( \alpha \)) ### Step 3: Write Down the Contributions to Mass and Atomic Numbers - **Positron**: - Mass number = 0 - Atomic number = +1 - **Alpha particles** (2 emissions): - Each alpha particle: - Mass number = 4 - Atomic number = +2 - Total for two alpha particles: - Mass number = \( 2 \times 4 = 8 \) - Atomic number = \( 2 \times 2 = 4 \) - **Beta particles** (2 emissions): - Each beta particle: - Mass number = 0 - Atomic number = -1 - Total for two beta particles: - Mass number = \( 0 \) - Atomic number = \( 2 \times (-1) = -2 \) ### Step 4: Conservation of Mass Number Using the conservation of mass number: \[ a = c + 0 + 8 + 0 + 4 \] This simplifies to: \[ a = c + 12 \] So, we have our first relationship: \[ c = a - 12 \] ### Step 5: Conservation of Atomic Number Using the conservation of atomic number: \[ b = d + 1 + 4 - 2 + 2 \] This simplifies to: \[ b = d + 5 \] Rearranging gives us: \[ d = b - 5 \] ### Step 6: Summary of Relationships From the above steps, we have derived two key relationships: 1. \( c = a - 12 \) 2. \( d = b - 5 \) ### Step 7: Conclusion The correct relationships derived from the decay process are: - \( a = c + 12 \) - \( d = b - 5 \) Thus, the correct option is: **Option 1: \( a = c + 12 \) and \( d = b - 5 \)**. ---

To solve the problem, we need to analyze the decay process of the species \( bX^{(a)} \) and derive the relationships between the mass numbers and atomic numbers of the parent and daughter species. Here is a step-by-step solution: ### Step 1: Identify the Initial and Final Species - The initial species is \( bX^{(a)} \) where: - Mass number (A) = \( a \) - Atomic number (Z) = \( b \) - The final species after decay is \( dY^{(c)} \) where: ...
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