The element `Z=114` has been discovered recently. It will belong to which of the family`//`group and electronic configuration?

Options

A. Halogen family , `[Rn] 5f^(14) 6d^(10) 7s^(2) 7 p^(5)`
B. Carbon family, `[Rn] 5f^(14) 6d^(10)7s^(2)7p^(2)`
C. Oxygen family `[Rn] 5f^(14) 6d^(10)7s^(2)7p^(4)`
D. Nitrogen family `[Rn] 5f^(14) 6d^(10)7s^(2)7p^(6)`

Explanation

To determine the group and electronic configuration of the element with atomic number Z=114, we can follow these steps:

### Step 1: Identify the element
The element with atomic number 114 is known as Flerovium (Fl).

### Step 2: Determine the electronic configuration
To find the electronic configuration of Flerovium, we start from the last noble gas, which is Radon (Rn, atomic number 86). The electronic configuration of Radon is:

\[ \text{Rn: } [Xe] 4f^{14} 5d^{10} 6s^{2} 6p^{6} \]

Now, we need to add the remaining electrons to reach atomic number 114. The total number of electrons in Flerovium is 114, so we have:

- Radon (86 electrons)
- 6s has 2 electrons (total 88)
- 6p has 6 electrons (total 94)
- 7s has 2 electrons (total 96)
- 5f has 14 electrons (total 110)
- 6d has 10 electrons (total 120), but we only need 4 more to reach 114.

Thus, the electronic configuration of Flerovium (Z=114) is:

\[ \text{Fl: } [Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{2} \]

### Step 3: Determine the group or family
Flerovium is located in Group 14 of the periodic table, which is also known as the Carbon family. The general electronic configuration for elements in Group 14 is \( ns^2 np^2 \). Since Flerovium has 2 electrons in the 7s orbital and 2 electrons in the 7p orbital, it fits this configuration.

### Final Answer
- **Group/Family**: Group 14 (Carbon family)
- **Electronic Configuration**: \[ [Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{2} \]

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