The electronic configuration of an element is `1s^(2)2s^(2)2p^(6),3s^(2)3p^(5)`. The atomic number of element present just below the above element in periodic table is:

Options

A. (a) 33
B. (b) 35
C. (c) 36
D. (d) 49

Explanation

To find the atomic number of the element present just below the given element in the periodic table, we can follow these steps:

### Step 1: Determine the Electronic Configuration
The electronic configuration given is:
\[ 1s^2 2s^2 2p^6 3s^2 3p^5 \]

### Step 2: Count the Total Number of Electrons
To find the atomic number, we need to count the total number of electrons in the configuration:
- \( 1s^2 \) contributes 2 electrons
- \( 2s^2 \) contributes 2 electrons
- \( 2p^6 \) contributes 6 electrons
- \( 3s^2 \) contributes 2 electrons
- \( 3p^5 \) contributes 5 electrons

Adding these together:
\[ 2 + 2 + 6 + 2 + 5 = 17 \]

### Step 3: Identify the Element
The total number of electrons (or atomic number) is 17. The element with atomic number 17 is Chlorine (Cl).

### Step 4: Determine the Group and Period
Chlorine is in Group 17 (the halogens) and Period 3 of the periodic table.

### Step 5: Identify the Element Below Chlorine
The element directly below Chlorine in the periodic table is Bromine (Br), which is in the same group (Group 17) but in Period 4.

### Step 6: Find the Atomic Number of Bromine
The atomic number of Bromine is 35.

### Conclusion
Thus, the atomic number of the element present just below Chlorine in the periodic table is:
**35**